1890 New Hampshire gubernatorial election

The 1890 New Hampshire gubernatorial election was held on November 4, 1890. Republican nominee Hiram A. Tuttle defeated Democratic nominee Charles H. Amsden with 49.26% of the vote.

1890 New Hampshire gubernatorial election
November 4, 1890
 
Nominee Hiram A. Tuttle Charles H. Amsden
Party Republican Democratic
Popular vote 42,479 42,386
Percentage 49.26% 49.15%
Governor before election

David H. Goodell
Republican

 Elected Governor

Hiram A. Tuttle
Republican

Elections in New Hampshire
Federal government
Presidential elections
United States Senate elections
United States House elections
State government
Gubernatorial elections
Executive Council elections
General Court elections
Senate elections
House elections
Manchester
Mayoral elections

General election

Candidates

Major party candidates

  • Hiram A. Tuttle, Republican
  • Charles H. Amsden, Democratic

Other candidates

  • Josiah M. Fletcher, Prohibition

Results
1890 New Hampshire gubernatorial election[1]
Party Candidate Votes % ±%
Republican Hiram A. Tuttle 42,479 49.26%
Democratic Charles H. Amsden 42,386 49.15%
Prohibition Josiah M. Fletcher 1,343 1.56%
Majority 93
Turnout
Republican hold Swing

References
  1. Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved 2020-07-16.
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